-0.028x^2+2,8x=x

Solution for -0.028x^2+2,8x=x equation:

-0.028x^2+2.8x=x

We move all terms to the left:

-0.028x^2+2.8x-(x)=0

We add all the numbers together, and all the variables

-0.028x^2+1.8x=0

a = -0.028; b = 1.8; c = 0;
Δ = b2-4ac
Δ = 1.82-4·(-0.028)·0
Δ = 3.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.8)-\sqrt{3.24}}{2*-0.028}=\frac{-1.8-\sqrt{3.24}}{-0.056}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.8)+\sqrt{3.24}}{2*-0.028}=\frac{-1.8+\sqrt{3.24}}{-0.056}
$